When do we get maximum range in a simple projectile motion?
(a) When θ = 45°
(b) When θ = 60°
(c) When θ = 90°
(d) When θ = 0°
The question was posed to me during an internship interview.
The doubt is from Simple Projectile Motion in chapter Motion in a Plane of Physics – Class 11
Select the correct answer from above options
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Easiest explanation: The formula for horizontal range is R = v^2(sin 2θ)/g. This will be maximum when sin 2θ = 1, which implies that 2θ = 90°, which in turn implies that θ = 45°. Hence the correct answer is when θ = 45°.
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