# What will be the general solution of the differential equation d^2y/dx^2 = e^2x(12 cos3x – 5 sin3x)? (here, A and B are integration constant)

Category: QuestionsWhat will be the general solution of the differential equation d^2y/dx^2 = e^2x(12 cos3x – 5 sin3x)? (here, A and B are integration constant)
Editor">Editor Staff asked 11 months ago

What will be the general solution of the differential equation d^2y/dx^2 = e^2x(12 cos3x – 5 sin3x)? (here, A and B are integration constant)

(a) y = e^x sin3x + Ax + B

(b) y = e^2x sin3x + Ax + B

(c) y = e^2x sin3x + A

This question is from Linear Second Order Differential Equations in section Differential Equations of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options
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Editor">Editor Staff answered 11 months ago

The correct option is (b) y = e^2x sin3x + Ax + B

The explanation is: Given, d^2y/dx^2 = e^2x(12 cos3x – 5 sin3x) ………(1)

Integrating (1) we get,

dy/dx = 12∫ e^2xcos3x dx – 5∫ e^2x sin3x dx

= 12 * (e^2x/2^2 + 3^2)[2cos3x + 3sin3x] – 5 * (e^2x/2^2 + 3^2)[2sin3x – 3cos3x] + A (A is integrationconstant)

So dy/dx = e^2x/13 [24 cos3x + 36 sin3x – 10 sin3x + 15 cos3x] + A

= e^2x/13(39 cos3x + 26 sin3x) + A

=> dy/dx = e^2x(3 cos3x + 2 sin3x) + A ……….(2)

Again integrating (2) we get,

y = 3*∫ e^2x cos3xdx + 2∫ e^2x sin3xdx + A ∫dx

y = 3*(e^2x/2^2 + 3^2)[2cos3x + 3sin3x] + 2*(e^2x/2^2 + 3^2)[2sin3x – 3cos3x] + Ax + B   (B is integration constant)

y = e^2x/13(6 cos3x + 9 sin3x + 4 sin3x – 6 cos3x) + Ax + B

or, y = e^2x sin3x + Ax + B