Using Carius method, find out the percentage of bromine in the compound if 0.450 g of organic compound gave 0.200 g of AgBr. (Given: molar mass of Ag = 108; molar mass of Br = 80)
This question was addressed to me in semester exam.
Question is from Organic Chemistry in chapter Organic Chemistry – Basic Principles and Technique of Chemistry – Class 11
Select the correct answer from above options
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The correct choice is (d) 18.91%
For explanation: The molar mass of AgBr = 108 + 80
= 188 g
So, 188 g of AgBr contains 80 g of Br.
Then, 0.200 g of AgBr contains 80 * 0.200/ 188 = 0.085 g bromine
Therefore, percentage of bromine = 0.085 * 100/ 0.450
Thus, the percentage of bromine (halogen) using Carius method is 18.91%.