For the given equation (x+2) (x+4) = x^2 + 6x + 8, how many values of x satisfies this equation?

(a) Two values of x

(b) One value of x

(c) All value of x

(d) No value of x

I got this question by my college professor while I was bunking the class.

Query is from Integration by Partial Fractions in section Integrals of Mathematics – Class 12

NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options

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Right option is (c) All value of x

The explanation: If we solve the L.H.S. (Left Hand Side) of the equation, we get the following value.

(x+2) (x+4) = x^2 + 4x + 2x + 8 = x^2 + 6x + 8.

This value is same as the R.H.S. (Right Hand Side).

So, all the values of x satisfy the equality.