For the given equation (x+2) (x+4) = x^2 + 6x + 8, how many values of x satisfies this equation?

Category: QuestionsFor the given equation (x+2) (x+4) = x^2 + 6x + 8, how many values of x satisfies this equation?
Editor">Editor Staff asked 11 months ago

For the given equation (x+2) (x+4) = x^2 + 6x + 8, how many values of x satisfies this equation?
 
(a) Two values of x
 
(b) One value of x
 
(c) All value of x
 
(d) No value of x
 
I got this question by my college professor while I was bunking the class.
 
Query is from Integration by Partial Fractions in section Integrals of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options 
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1 Answers
Editor">Editor Staff answered 11 months ago

Right option is (c) All value of x
 
The explanation: If we solve the L.H.S. (Left Hand Side) of the equation, we get the following value.
 
(x+2) (x+4) = x^2 + 4x + 2x + 8 = x^2 + 6x + 8.
 
This value is same as the R.H.S. (Right Hand Side).
 
So, all the values of x satisfy the equality.