Find the angle between the pair of lines \(\frac{x-3}{5}=\frac{y+7}{3}=\frac{z-2}{2} \,and \,\frac{x+1}{3}=\frac{y-5}{4}=\frac{z+2}{8}\).

Category: QuestionsFind the angle between the pair of lines \(\frac{x-3}{5}=\frac{y+7}{3}=\frac{z-2}{2} \,and \,\frac{x+1}{3}=\frac{y-5}{4}=\frac{z+2}{8}\).
Editor">Editor Staff asked 11 months ago

Find the angle between the pair of lines \frac{x-3}{5}=\frac{y+7}{3}=\frac{z-2}{2} \,and \,\frac{x+1}{3}=\frac{y-5}{4}=\frac{z+2}{8}.
 
(a) cos^{-1}⁡\frac{43}{\sqrt{3482}}
 
(b) cos^{-1}⁡⁡\frac{43}{\sqrt{3382}}
 
(c) cos^{-1}⁡⁡\frac{85}{\sqrt{3382}}
 
(d) cos^{-1}⁡⁡\frac{34}{\sqrt{3382}}
 
This question was addressed to me in an online interview.
 
The origin of the question is Three Dimensional Geometry topic in portion Three Dimensional Geometry of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options 
Interview Questions and Answers, Database Interview Questions and Answers for Freshers and Experience

1 Answers
Editor">Editor Staff answered 11 months ago

The correct answer is (b) cos^{-1}⁡⁡\frac{43}{\sqrt{3382}}
 
Easy explanation: The direction ratios are 5, 3, 2 for L1 and 3, 4, 8 for L2
 
∴ the angle between the two lines is given by
 
cos⁡θ=\frac{(a_1 a_2+b_1 b_2+c_1 c_2)}{\sqrt{a_1^2+b_1^2+c_1^2} \sqrt{a_2^2+b_2^2+c_2^2}}
 
=\frac{15+12+16}{\sqrt{5^2+3^2+2^2}.\sqrt{3^2+4^2+8^2}}
 
=\frac{43}{\sqrt{38}.\sqrt{89}}=\frac{43}{\sqrt{3382}}
 
θ=cos^{-1}⁡\frac{43}{\sqrt{3382}}.