Find \int_1^2\sqrt{x}-3x \,dx.

Category: QuestionsFind \int_1^2\sqrt{x}-3x \,dx.
Editor">Editor Staff asked 11 months ago

Find \int_1^2\sqrt{x}-3x \,dx.
(a) \frac{8\sqrt{2}-31}{6}
(b) 8\sqrt{2}-31
(c) \frac{\sqrt{2}-31}{3}
(d) \frac{8\sqrt{2}+31}{4}
This question was posed to me in an interview for job.
My query is from Fundamental Theorem of Calculus-2 topic in section Integrals of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options 
Interview Questions and Answers, Database Interview Questions and Answers for Freshers and Experience

1 Answers
Editor">Editor Staff answered 11 months ago

Right answer is (a) \frac{8\sqrt{2}-31}{6}
The best I can explain: Let I=\int_1^2 \sqrt{x}-3x \,dx
F(x)=\int \sqrt{x}-3x \,dx
By using the second fundamental theorem of calculus, we get