A solid sphere is given a horizontal velocity of 4m/s on a flat surface. What will be its velocity when it starts pure rolling? Mass = 2kg, Radius = 5cm. Coefficient of friction = 0.3.
(a) It cannot roll purely
(b) 2/3 s
I have been asked this question at a job interview.
Query is from Rolling Motion in section System of Particles and Rotational Motion of Physics – Class 11
Select the correct answer from above options
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Correct option is (b) 2/3 s
Easy explanation: Friction force ‘f’ will cause its speed to come down & increase its angular speed till V=Rw.
f = μN = 0.3*2*10 = 6N.
Thus, deceleration ‘a’ = 6/2 = 3m/s^2.
And, angular acceleration = a/R = 3/0.05 = 60 rad/s^2.
v = v0 – at = 4 – 3t.
w = w0 + (a/R)t = 0 + 60t = 60t.
At pure rolling, v=Rw
⇒ 4 – 3t = 0.05(60t)
∴ 4 = 3t + 3t = 6t.
∴ t = 2/3 s.