A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t^2 – 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?

(a) 10cm/sec^2

(b) 12cm/sec^2

(c) 14cm/sec^2

(d) 16cm/sec^2

This question was posed to me in unit test.

Question is from Calculus Application topic in division Application of Calculus of Mathematics – Class 12

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