A particle is projected vertically upwards with a velocity of 196 m/sec. How much will be the greatest height?

Category: QuestionsA particle is projected vertically upwards with a velocity of 196 m/sec. How much will be the greatest height?
Editor">Editor Staff asked 11 months ago

A particle is projected vertically upwards with a velocity of 196 m/sec. How much will be the greatest height?
 
(a) 1930 m
 
(b) 1960 m
 
(c) 1990 m
 
(d) 1995 m
 
The question was asked in a national level competition.
 
My query is from Calculus Application in division Application of Calculus of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options 
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1 Answers
Editor">Editor Staff answered 11 months ago

Correct choice is (b) 1960 m
 
For explanation I would say: Let the particle projected from A with velocity u = 196 m/sec and P be its position at time t where, AP = x m, if v m/sec be its velocity at P,then the equation of motion of the particle is,
 
dv/dt = -g [where, v = dx/dt]  ……….(1)
 
Since v = u, when t = 0, hence from (1) we get,
 
u∫^vdv = -g 0∫^tdt
 
Or v – u = -gt
 
Or dx/dt = u – gt ……….(2)
 
Since x = 0, when t = 0, hence from (2) we get,
 
0∫^x dx = 0∫^x (u – gt)dt
 
Or x = ut – (1/2)gt^2 ……….(3)
 
Again, (1) can be written as,
 
dv/dx*dx/dt = -g
 
Or v(dv/dx) = -g  ……….(4)
 
Since v = u, when x = 0, hence, from (4) we get,
 
u∫^vvdv = -g 0∫^xdx
 
Or v^2 = u^2 – 2gx  ……….(5)
 
If H m be the greatest height of the particle, then v = 0, when x = H; hence, from (5) we get,
 
0 = u^2 – 2gH
 
Or H = u^2/2g
 
= (196*196)/(2*9.8)   [as, g = 9.8 m/sec^2]
 
= 1960 m.