A particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t^3 – 12t + 11. What is the displacement of the particle at the end of 2 seconds?

Category: QuestionsA particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t^3 – 12t + 11. What is the displacement of the particle at the end of 2 seconds?
Editor">Editor Staff asked 11 months ago

A particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t^3 – 12t + 11. What is the displacement of the particle at the end of 2 seconds?
 
(a) 1 cm
 
(b) 2 cm
 
(c) 3 cm
 
(d) 4 cm
 
I got this question in an online interview.
 
This question is from Calculus Application topic in section Application of Calculus of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options 
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1 Answers
Editor">Editor Staff answered 11 months ago

The correct choice is (c) 3 cm
 
Easy explanation: We have, x = 2t^3 – 12t + 11 ……….(1)
 
Putting t = 2 in (1), we get,
 
Displacement = x = 2t^3 – 12t + 11
 
= 2(2)^3 – 12(2) + 11
 
= 3 cm.