A football is projected at an angle of 45° from the ground with an initial velocity of 10 m/s, take acceleration due to gravity is g = 10 m/s^2.What is the time of flight?
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A football is projected at an angle of 45° from the ground with an initial velocity of 10 m/s, take acceleration due to gravity is g = 10 m/s^2.What is the time of flight?
(a) 1.4142 s
(b) 1.5361 s
(c) 1.8987 s
(d) 1.5651 s
The question was posed to me in a job interview.
The question is from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11
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Explanation: The formula for time of flight is t = 2(v sinθ/g). Here, v = 10, θ = 45°, g = 10. Hence, on solving we will get the time of flight as 1.4142 s.
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