A car moving around a tree has the distance from the tree defined as r = 5t^2 + 7. What is the magnitude of the centripetal acceleration at t = 2s, if the angular velocity is 2 rad/s.

Category: QuestionsA car moving around a tree has the distance from the tree defined as r = 5t^2 + 7. What is the magnitude of the centripetal acceleration at t = 2s, if the angular velocity is 2 rad/s.
Editor">Editor Staff asked 1 year ago

A car moving around a tree has the distance from the tree defined as r = 5t^2 + 7. What is the magnitude of the centripetal acceleration at t = 2s, if the angular velocity is 2 rad/s.
 
(a) 102
 
(b) 108
 
(c) 59
 
(d) 54
 
I got this question in exam.
 
Query is from Non-Uniform Circular Motion in division Laws of Motion of Physics – Class 11
Select the correct answer from above options 
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1 Answers
Editor">Editor Staff answered 1 year ago

Right option is (b) 108
 
For explanation: The centripetal acceleration is given as ac = rω^2. Here, we have r = 5t^2 + 7 = 27 units at t = 2s. Angular velocity is 2 rad/s. On substituting all the values, we get, the acceleration as 108 units/s^2.