# A body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum horizontal range covered?

Category: QuestionsA body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum horizontal range covered?
Editor">Editor Staff asked 1 year ago

A body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum horizontal range covered?

(a) 54.13 m

(b) 49 m

(c) 49.16 m

(d) 60 m

I had been asked this question by my college director while I was bunking the class.

I’d like to ask this question from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11
Select the correct answer from above options
Interview Questions and Answers, Database Interview Questions and Answers for Freshers and Experience

Editor">Editor Staff answered 1 year ago

Correct choice is (a) 54.13 m

Explanation: The formula for horizontal range is R = v^2 (sin 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on solving we will get range as 54.13 m.

Notice: Trying to get property 'ID' of non-object in /home/fvckxqmi/public_html/wp-content/themes/blocksy/inc/single/single-helpers.php on line 17

Notice: Trying to get property 'ID' of non-object in /home/fvckxqmi/public_html/wp-content/themes/blocksy/inc/single/single-helpers.php on line 17

Notice: Trying to get property 'ID' of non-object in /home/fvckxqmi/public_html/wp-content/themes/blocksy/inc/single/single-helpers.php on line 17

Notice: Trying to get property 'ID' of non-object in /home/fvckxqmi/public_html/wp-content/themes/blocksy/inc/single/single-helpers.php on line 17
Articles: 40701