A body of mass 5 kg, projected at an angle of 45° from the ground covers a horizontal range of 45 m, acceleration due to gravity is g = 10 m/s^2, what is the velocity with which it was projected covered?

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Editor">Editor Staff asked 1 year ago

A body of mass 5 kg, projected at an angle of 45° from the ground covers a horizontal range of 45 m, acceleration due to gravity is g = 10 m/s^2, what is the velocity with which it was projected covered?
 
(a) 21.21 m/s
 
(b) 20 m/s
 
(c) 22 m/s
 
(d) 21.1 m/s
 
The question was asked in a national level competition.
 
My doubt stems from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11
Select the correct answer from above options 
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Editor">Editor Staff answered 1 year ago

Correct answer is (a) 21.21 m/s
 
The best I can explain: The formula for horizontal range is R = v^2 (sin 2θ)/g. Here, R = 45, θ = 45°, g = 10. Hence, on solving we will get velocity as 21.21 m/s. The result can be cross checked by putting this value of velocity and finding out the range.

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