A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?

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Editor">Editor Staff asked 1 year ago

A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?
 
(a) 1.15 units/s
 
(b) 11.5 units/s
 
(c) 115 units/s
 
(d) 0.0115 units/s
 
I had been asked this question by my college director while I was bunking the class.
 
This interesting question is from Motion in a Plane with Constant Acceleration topic in section Motion in a Plane of Physics – Class 11
Select the correct answer from above options 
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Editor">Editor Staff answered 1 year ago

Right answer is (a) 1.15 units/s
 
For explanation I would say: The distance between A and B is 13 units. The distance between B and C is 10 units. Hence, the total distance is 23 units. The total time taken is 20 s. Average speed = total distance/total time taken = 23/20 = 1.15 units/s.

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