# A ball of mass 100 g, projected at an angle of 30° from the ground with an initial velocity of 11 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum height attained?

Category: QuestionsA ball of mass 100 g, projected at an angle of 30° from the ground with an initial velocity of 11 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum height attained?
Editor">Editor Staff asked 1 year ago

A ball of mass 100 g, projected at an angle of 30° from the ground with an initial velocity of 11 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum height attained?

(a) 1.5 m

(b) 3.0 m

(c) 1.0 m

(d) 2.0 m

The question was posed to me by my school principal while I was bunking the class.

This is a very interesting question from Simple Projectile Motion in chapter Motion in a Plane of Physics – Class 11
Select the correct answer from above options
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1 Answers
Editor">Editor Staff answered 1 year ago

The correct choice is (a) 1.5 m

The best explanation: The formula for maximum height is h = (v sinθ)^2/2g. Here, v = 11, θ = 30°, g = 10. Hence, on solving we will get the maximum height attained as 1.5125 m. The value can be rounded off to 1.5.