# A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white and the first ball drawn is green? The balls are replaced in the bag.

Category: QuestionsA bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white and the first ball drawn is green? The balls are replaced in the bag.
Editor">Editor Staff asked 11 months ago

A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white and the first ball drawn is green? The balls are replaced in the bag.

(a) \frac {1}{9}

(b) \frac {2}{9}

(c) \frac {8}{81}

(d) \frac {2}{81}

My question is based upon Probability topic in division Probability of Mathematics – Class 12
NCERT Solutions for Subject Clas 12 Math Select the correct answer from above options
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Editor">Editor Staff answered 11 months ago

Right choice is (c)
8
81

For explanation I would say: Total number of balls = 9

The probability of the first ball to be white =
2
9

The probability of drawing green ball for the second time with replacement =
4
9

Total probability =
2
9
×
4
9
=
8
81